What is (x-3)^2=-8(y-4) ?

The solution to (x-3)^2=-8(y-4) is Parabola with (h,k)=(3,4),p=-2

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(x-3)^2=-8(y-4)

(x - 3)^{2} = - 8 (y - 4)

(h, k) = (3, 4), p = - 2

Solution steps

(x - 3)^{2} = - 8 (y - 4)

Rewrite

(x - 3)^{2} = - 8 (y - 4)

in the standard form:

4 (- 2) (y - 4) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 4), p = - 2

(x - 3)^{2} = - 8 (y - 3)

(x + 2)^{2} = 4 (y - 3)

x, x = 5 - 12.5 (t (x) + 2) + \frac{10.4 ( t ( x ) + 2 ) ^{2}}{2}

x^{2} - 10 x - 63 y = - 25 - 63

y^{2} - 28 x - 16 y + 8 = 0

What is (x-3)^2=-8(y-4) ?
The solution to (x-3)^2=-8(y-4) is Parabola with (h,k)=(3,4),p=-2