What is -f(x)=3(x)^2+2(x)-3 ?

The solution to -f(x)=3(x)^2+2(x)-3 is Parabola with (h,k)=(-1/3 , 10/3),p=-1/12

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-f(x)=3(x)^2+2(x)-3

- f (x) = 3 (x)^{2} + 2 (x) - 3

(h, k) = (- \frac{1}{3}, \frac{10}{3}), p = - \frac{1}{12}

Solution steps

- y = 3 x^{2} + 2 x - 3

Rewrite

- y = 3 x^{2} + 2 x - 3

in the standard form

4 (- \frac{1}{12}) (y - \frac{10}{3}) = (x - (- \frac{1}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{3}, \frac{10}{3}), p = - \frac{1}{12}

- f (x) = 3 (x)^{2} + 2 (x) - 2

x^{2} - 16 x + 12 y + 100 = 0

x, x + 1 = u (x)^{2}

4 x^{2} + 12 x + 48 y - 159 = 0

x^{2} - 2 x + 6 y + 13 = 0

What is -f(x)=3(x)^2+2(x)-3 ?
The solution to -f(x)=3(x)^2+2(x)-3 is Parabola with (h,k)=(-1/3 , 10/3),p=-1/12