What is ((x+2)/5)^2+((y+2)/3)=10 ?

The solution to ((x+2)/5)^2+((y+2)/3)=10 is Parabola with (h,k)=(-2,28),p=-25/12

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((x+2)/5)^2+((y+2)/3)=10

(\frac{x + 2}{5})^{2} + (\frac{y + 2}{3}) = 10

(h, k) = (- 2, 28), p = - \frac{25}{12}

Solution steps

(\frac{x + 2}{5})^{2} + \frac{y + 2}{3} = 10

Rewrite

(\frac{x + 2}{5})^{2} + \frac{y + 2}{3} = 10

in the standard form:

4 (- \frac{25}{12}) (y - 28) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 28), p = - \frac{25}{12}

x = - 2 y^{2} + 6 y

y - (x - 2)^{2} = 0

x - 5 = (y - 3)^{2}

\frac{x}{4} x + 12 y = 12

4 x + 1 = - 6 w (x, y) y

What is ((x+2)/5)^2+((y+2)/3)=10 ?
The solution to ((x+2)/5)^2+((y+2)/3)=10 is Parabola with (h,k)=(-2,28),p=-25/12