What is f(x)=x^2-2x-6f(2)-f(t) ?

The solution to f(x)=x^2-2x-6f(2)-f(t) is Parabola with (h,k)=(-(-f-2)/2 ,(-f^2-52f-4)/(4f)),p= f/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=x^2-2x-6f(2)-f(t)

f (x) = x^{2} - 2 x - 6 f (2) - f (t)

(h, k) = (- \frac{- f - 2}{2}, \frac{- f ^{2} - 52 f - 4}{4 f}), p = \frac{f}{4}

Solution steps

f x = x^{2} - 2 x - 6 f \cdot 2 - f t

Rewrite

f x = x^{2} - 2 x - 6 f \cdot 2 - f t

in the standard form

4 \cdot \frac{f}{4} (t - \frac{- f ^{2} - 52 f - 4}{4 f}) = (x - (- \frac{- f - 2}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{- f - 2}{2}, \frac{- f ^{2} - 52 f - 4}{4 f}), p = \frac{f}{4}

2 x + 3 y^{2} = 7

x^{2} = 5 x - 3 k (x) + 3

2 x + 3 y^{2} = 1

4 y^{2} - 8 y + 3 x = 2

f (x) (x)^{- 1} = \frac{x - 4}{11}

What is f(x)=x^2-2x-6f(2)-f(t) ?
The solution to f(x)=x^2-2x-6f(2)-f(t) is Parabola with (h,k)=(-(-f-2)/2 ,(-f^2-52f-4)/(4f)),p= f/4