What is 4x^2+2x=y-2-x^2 ?

The solution to 4x^2+2x=y-2-x^2 is Parabola with (h,k)=(-1/5 , 9/5),p= 1/20

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4x^2+2x=y-2-x^2

4 x^{2} + 2 x = y - 2 - x^{2}

(h, k) = (- \frac{1}{5}, \frac{9}{5}), p = \frac{1}{20}

Solution steps

4 x^{2} + 2 x = y - 2 - x^{2}

Rewrite

4 x^{2} + 2 x = y - 2 - x^{2}

in the standard form

4 \cdot \frac{1}{20} (y - \frac{9}{5}) = (x - (- \frac{1}{5}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{5}, \frac{9}{5}), p = \frac{1}{20}

4 x^{2} + 6 x^{2} + 4 x - 2 y = 0

17 x^{2} + 16 y = 272

6 x^{2} + 7 x + k (x) = 0

- y = 1 - x^{2}

y + 61 = 2 x (x - 61)

What is 4x^2+2x=y-2-x^2 ?
The solution to 4x^2+2x=y-2-x^2 is Parabola with (h,k)=(-1/5 , 9/5),p= 1/20