What is x+y^2+14x-14y+73=0 ?

The solution to x+y^2+14x-14y+73=0 is Parabola with (h,k)=(-8/5 ,7),p=-15/4

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x+y^2+14x-14y+73=0

x + y^{2} + 14 x - 14 y + 73 = 0

(h, k) = (- \frac{8}{5}, 7), p = - \frac{15}{4}

Solution steps

x + y^{2} + 14 x - 14 y + 73 = 0

Rewrite

x + y^{2} + 14 x - 14 y + 73 = 0

in the standard form

4 (- \frac{15}{4}) (x - (- \frac{8}{5})) = (y - 7)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{8}{5}, 7), p = - \frac{15}{4}

y - 2 x^{2} + 12 x + 8 = 0

x^{2} - \frac{3}{2} y = 0

(x + 1)^{2} = - \frac{3}{2} (y - \frac{4}{3} x - \frac{2}{3})

x^{2} + 2 x + 1 = 16 y

- x^{2} + 121 s = 0

What is x+y^2+14x-14y+73=0 ?
The solution to x+y^2+14x-14y+73=0 is Parabola with (h,k)=(-8/5 ,7),p=-15/4