What is 2x^2-20x-2m(x)>0 ?

The solution to 2x^2-20x-2m(x)>0 is Parabola with (h,k)=(5,-25),p= 1/4

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2x^2-20x-2m(x)>0

2 x^{2} - 20 x - 2 m (x) > 0

(h, k) = (5, - 25), p = \frac{1}{4}

Solution steps

2 x^{2} - 20 x - 2 y > 0

Rewrite

2 x^{2} - 20 x - 2 y > 0

in the standard form

4 \cdot \frac{1}{4} (y - (- 25)) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, - 25), p = \frac{1}{4}

y - 3 = x^{2} - 4 x

y^{2} - \frac{1}{5} x + 2 y = - \frac{19}{5}

x = (h (x) + 1)^{2}

x + 5 y^{2} + y - 4 ey = 2 x

(y + 2)^{2} = 32 (x - 3)

What is 2x^2-20x-2m(x)>0 ?
The solution to 2x^2-20x-2m(x)>0 is Parabola with (h,k)=(5,-25),p= 1/4