en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci x^2+x+1

Solution

foci

x^{2} + x + 1

Solution

(- \frac{1}{2}, 1)

Solution steps

Rewrite

y = x^{2} + x + 1

in the standard form

4 \cdot \frac{1}{4} (y - \frac{3}{4}) = (x - (- \frac{1}{2}))^{2}

(h, k) = (- \frac{1}{2}, \frac{3}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{1}{2}, \frac{3}{4})

along the y-axis

(- \frac{1}{2}, \frac{3}{4} + p)

= (- \frac{1}{2}, \frac{3}{4} + \frac{1}{4})

Refine

(- \frac{1}{2}, 1)

Popular Examples

vertices (x^2}{16}+\frac{y^2)/9 =1 vertices

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

x^2+y^2-2x+6y+6=0

x^{2} + y^{2} - 2 x + 6 y + 6 = 0

axis y=-x^2+4x+1 axis

y = - x^{2} + 4 x + 1

25 x^{2} + 9 y^{2} = 225

vertices (y^2}{64}-\frac{x^2)/9 =1 vertices

\frac{y ^{2}}{64} - \frac{x ^{2}}{9} = 1

Frequently Asked Questions (FAQ)

What is the foci x^2+x+1 ?
The foci x^2+x+1 is (-1/2 ,1)