What is the axis y=-x^2+4x+1 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=-x^2+4x+1

axis

y = - x^{2} + 4 x + 1

x = 2

Solution steps

y = - x^{2} + 4 x + 1

Rewrite

y = - x^{2} + 4 x + 1

in the standard form

4 (- \frac{1}{4}) (y - 5) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 5), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

25 x^{2} + 9 y^{2} = 225

\frac{y ^{2}}{64} - \frac{x ^{2}}{9} = 1

x^{2} + 4 y^{2} - 6 x + 16 y + 21 = 0

x^{2} + y^{2} - 6 x + 4 y + 9 = 0

f (x) = x^{2} - 4 x + 3