What is 4x^2-1/2 x^2+8x-2y=-2 ?

The solution to 4x^2-1/2 x^2+8x-2y=-2 is Parabola with (h,k)=(-8/7 ,-9/7),p= 1/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2-1/2 x^2+8x-2y=-2

4 x^{2} - \frac{1}{2} x^{2} + 8 x - 2 y = - 2

(h, k) = (- \frac{8}{7}, - \frac{9}{7}), p = \frac{1}{7}

Solution steps

4 x^{2} - \frac{1}{2} x^{2} + 8 x - 2 y = - 2

Rewrite

4 x^{2} - \frac{1}{2} x^{2} + 8 x - 2 y = - 2

in the standard form

4 \cdot \frac{1}{7} (y - (- \frac{9}{7})) = (x - (- \frac{8}{7}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{8}{7}, - \frac{9}{7}), p = \frac{1}{7}

x = - 3 (y + 1)^{2} + 2

- \frac{1}{4} (x - 8) = (y + 5)^{2}

x^{2} = - 8 (y + 1)

x^{2} - 8 x + y + 8 y + 31 = 0

x 4 x + 3 y = 852

What is 4x^2-1/2 x^2+8x-2y=-2 ?
The solution to 4x^2-1/2 x^2+8x-2y=-2 is Parabola with (h,k)=(-8/7 ,-9/7),p= 1/7