What is x^2+(y-2)^2=1 ?

The solution to x^2+(y-2)^2=1 is Circle with (a,b)=(0,2),r=1

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x^2+(y-2)^2=1

x^{2} + (y - 2)^{2} = 1

(a, b) = (0, 2), r = 1

Solution steps

x^{2} + (y - 2)^{2} = 1

Rewrite

x^{2} + (y - 2)^{2} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 2)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 2), r = 1

16 x^{2} + y^{2} = 16

f (x) = x^{2} - 2

x^{2} + y^{2} - 9 = 0

y^{2} = 20 x

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

What is x^2+(y-2)^2=1 ?
The solution to x^2+(y-2)^2=1 is Circle with (a,b)=(0,2),r=1