What is -6y^2+4y=x+3y-2 ?

The solution to -6y^2+4y=x+3y-2 is Parabola with (h,k)=(49/24 , 1/12),p=-1/24

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-6y^2+4y=x+3y-2

- 6 y^{2} + 4 y = x + 3 y - 2

(h, k) = (\frac{49}{24}, \frac{1}{12}), p = - \frac{1}{24}

Solution steps

- 6 y^{2} + 4 y = x + 3 y - 2

Rewrite

- 6 y^{2} + 4 y = x + 3 y - 2

in the standard form

4 (- \frac{1}{24}) (x - \frac{49}{24}) = (y - \frac{1}{12})^{2}

Therefore parabola properties are:

(h, k) = (\frac{49}{24}, \frac{1}{12}), p = - \frac{1}{24}

5 y^{2} - z - 6 = 0

x^{2} - 12 x - 4 y + 20 = 0

x^{2} - 8 x - 4 y = 0

x^{2} + (- 14) x + 12 y = 36

x^{2} = 8 y + 2

What is -6y^2+4y=x+3y-2 ?
The solution to -6y^2+4y=x+3y-2 is Parabola with (h,k)=(49/24 , 1/12),p=-1/24