What is y+9= 3/2 (x+2)23(x+2) ?

The solution to y+9= 3/2 (x+2)23(x+2) is Parabola with (h,k)=(-2,-9),p= 1/138

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y+9= 3/2 (x+2)23(x+2)

y + 9 = \frac{3}{2} (x + 2) 23 (x + 2)

(h, k) = (- 2, - 9), p = \frac{1}{138}

Solution steps

y + 9 = \frac{3}{2} (x + 2) \cdot 23 (x + 2)

Rewrite

y + 9 = \frac{3}{2} (x + 2) \cdot 23 (x + 2)

in the standard form

4 \cdot \frac{1}{138} (y - (- 9)) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 9), p = \frac{1}{138}

x^{2} + 4 y + 4 x = 0

(y - 1)^{2} - x = 3

2 y - 3 x^{2} + 3 = 0

y = 2 x^{2} + 8 x + 13

2 x^{2} - 8 \cdot (- 6) y + 10 = 0

What is y+9= 3/2 (x+2)23(x+2) ?
The solution to y+9= 3/2 (x+2)23(x+2) is Parabola with (h,k)=(-2,-9),p= 1/138