What is x^2+10x+25=x+k(x) ?

The solution to x^2+10x+25=x+k(x) is Parabola with (h,k)=(-9/2 , 19/4),p= 1/4

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x^2+10x+25=x+k(x)

x^{2} + 10 x + 25 = x + k (x)

(h, k) = (- \frac{9}{2}, \frac{19}{4}), p = \frac{1}{4}

Solution steps

x^{2} + 10 x + 25 = x + y

Rewrite

x^{2} + 10 x + 25 = x + y

in the standard form

4 \cdot \frac{1}{4} (y - \frac{19}{4}) = (x - (- \frac{9}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{9}{2}, \frac{19}{4}), p = \frac{1}{4}

9 x^{2} - 4 (y - 2) - 36 \geq 0

x^{2} - 13 x + 42 = o

y \frac{y + 1}{x + 0} = 3

f (x) = x^{2} + 12 x + 27

5 y^{2} - 35 x - 40 x - 25 = 0

What is x^2+10x+25=x+k(x) ?
The solution to x^2+10x+25=x+k(x) is Parabola with (h,k)=(-9/2 , 19/4),p= 1/4