What is 2f(x)=-3x^2+x-1 ?

The solution to 2f(x)=-3x^2+x-1 is Parabola with (h,k)=(1/6 ,-11/24),p=-1/6

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2f(x)=-3x^2+x-1

2 f (x) = - 3 x^{2} + x - 1

(h, k) = (\frac{1}{6}, - \frac{11}{24}), p = - \frac{1}{6}

Solution steps

2 y = - 3 x^{2} + x - 1

Rewrite

2 y = - 3 x^{2} + x - 1

in the standard form

4 (- \frac{1}{6}) (y - (- \frac{11}{24})) = (x - \frac{1}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{6}, - \frac{11}{24}), p = - \frac{1}{6}

x^{2} + 10 x - y = 0

x = a t^{2}

6 = a b^{- 2}

- 4 x^{2} + 8 y + 64 = 0

3 (x + \frac{3}{4}) + 3 (y - \frac{1}{2})^{2} = 36

What is 2f(x)=-3x^2+x-1 ?
The solution to 2f(x)=-3x^2+x-1 is Parabola with (h,k)=(1/6 ,-11/24),p=-1/6