What are the solutions to the equation solvefor x,S(x)^1=x(40-2x) ?

The solutions to the equation solvefor x,S(x)^1=x(40-2x) are x=0,x=-S/2+20

Find the zeros of solvefor x,S(x)^1=x(40-2x)

The zeros of solvefor x,S(x)^1=x(40-2x) are x=0,x=-S/2+20

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solve for

x, S (x)^{1} = x (40 - 2 x)

x = 0, x = - \frac{S}{2} + 20

Solution steps

S x^{1} = x (40 - 2 x)

Move

x (40 - 2 x)

to the left side

S x^{1} - x (40 - 2 x) = 0

Factor

S x^{1} - x (40 - 2 x) : x (S + 2 (x - 20))

x (S + 2 (x - 20)) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or S + 2 (x - 20) = 0

Solve

S + 2 (x - 20) = 0 : x = - \frac{S}{2} + 20

The solutions to the quadratic equation are:

x = 0, x = - \frac{S}{2} + 20

6 y = (x + 2)^{2} - 2

5 x^{2} = 3 y

(\frac{13}{12} - 1) 3 y^{2} - 6 y - x = 0

x^{2} - 6 x - 4 y + 17 = 0

y > x^{2} - 4 x + 2

What are the solutions to the equation solvefor x,S(x)^1=x(40-2x) ?
The solutions to the equation solvefor x,S(x)^1=x(40-2x) are x=0,x=-S/2+20
Find the zeros of solvefor x,S(x)^1=x(40-2x)
The zeros of solvefor x,S(x)^1=x(40-2x) are x=0,x=-S/2+20