What is x^2-9x^2+20y-80x-2=0 ?

The solution to x^2-9x^2+20y-80x-2=0 is Parabola with (h,k)=(-5,-99/10),p= 5/8

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x^2-9x^2+20y-80x-2=0

x^{2} - 9 x^{2} + 20 y - 80 x - 2 = 0

(h, k) = (- 5, - \frac{99}{10}), p = \frac{5}{8}

Solution steps

x^{2} - 9 x^{2} + 20 y - 80 x - 2 = 0

Rewrite

x^{2} - 9 x^{2} + 20 y - 80 x - 2 = 0

in the standard form

4 \cdot \frac{5}{8} (y - (- \frac{99}{10})) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - \frac{99}{10}), p = \frac{5}{8}

(y + 2)^{2} = 3 (x - \frac{11}{3})

(y + 2)^{2} = 16 (x + 2)

15 = \frac{\frac{\frac{x}{5 + R ( x )}}{R ( x )}}{15}

(x - 2)^{2} + (y - 0)^{2} = (x + 3)^{2}

y^{2} + 16 x - 6 y - 7 = 0

What is x^2-9x^2+20y-80x-2=0 ?
The solution to x^2-9x^2+20y-80x-2=0 is Parabola with (h,k)=(-5,-99/10),p= 5/8