What is 4x^2-20x-24y+96=0 ?

The solution to 4x^2-20x-24y+96=0 is Parabola with (h,k)=(5/2 , 71/24),p= 3/2

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4x^2-20x-24y+96=0

4 x^{2} - 20 x - 24 y + 96 = 0

(h, k) = (\frac{5}{2}, \frac{71}{24}), p = \frac{3}{2}

Solution steps

4 x^{2} - 20 x - 24 y + 96 = 0

Rewrite

4 x^{2} - 20 x - 24 y + 96 = 0

in the standard form

4 \cdot \frac{3}{2} (y - \frac{71}{24}) = (x - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, \frac{71}{24}), p = \frac{3}{2}

y^{2} + 10 y + 2 x - 24 = 0

y \leq (x + 3)^{2} - 2

y = x^{2} + 4 x - 24

(y - 2)^{2} = 6 (x - 1)

f (x) = - x^{2} + 5 - 2

What is 4x^2-20x-24y+96=0 ?
The solution to 4x^2-20x-24y+96=0 is Parabola with (h,k)=(5/2 , 71/24),p= 3/2