What is x^2+y^2+8x-2y-19=0 ?

The solution to x^2+y^2+8x-2y-19=0 is Circle with (a,b)=(-4,1),r=6

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x^2+y^2+8x-2y-19=0

x^{2} + y^{2} + 8 x - 2 y - 19 = 0

(a, b) = (- 4, 1), r = 6

Solution steps

x^{2} + y^{2} + 8 x - 2 y - 19 = 0

Rewrite

x^{2} + y^{2} + 8 x - 2 y - 19 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 1)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 4, 1), r = 6

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

x^{2} + 4 x - 4 y = 0

y^{2} - 4 x = 0

16 x^{2} + y^{2} = 16

y^{2} = 3 x

What is x^2+y^2+8x-2y-19=0 ?
The solution to x^2+y^2+8x-2y-19=0 is Circle with (a,b)=(-4,1),r=6