What is 15x+3y=7-5x+4*9y^2 ?

The solution to 15x+3y=7-5x+4*9y^2 is Parabola with (h,k)=(111/320 , 1/24),p= 5/36

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15x+3y=7-5x+4*9y^2

15 x + 3 y = 7 - 5 x + 4 \cdot 9 y^{2}

(h, k) = (\frac{111}{320}, \frac{1}{24}), p = \frac{5}{36}

Solution steps

15 x + 3 y = 7 - 5 x + 4 \cdot 9 y^{2}

Rewrite

15 x + 3 y = 7 - 5 x + 4 \cdot 9 y^{2}

in the standard form

4 \cdot \frac{5}{36} (x - \frac{111}{320}) = (y - \frac{1}{24})^{2}

Therefore parabola properties are:

(h, k) = (\frac{111}{320}, \frac{1}{24}), p = \frac{5}{36}

3 x^{2} + 5 y - 6 = 0

x^{2} - 4 x - 4 y - 32 = 0

X^{2} + 2 Y = 6

(\frac{1}{6}) (x^{2} + 3 x - 4) = p (x) 6

y^{2} + 6 y + 9 = 4 x

What is 15x+3y=7-5x+4*9y^2 ?
The solution to 15x+3y=7-5x+4*9y^2 is Parabola with (h,k)=(111/320 , 1/24),p= 5/36