What is x^2+y^2+6x-4y=0 ?

The solution to x^2+y^2+6x-4y=0 is Circle with (a,b)=(-3,2),r=sqrt(13)

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x^2+y^2+6x-4y=0

x^{2} + y^{2} + 6 x - 4 y = 0

(a, b) = (- 3, 2), r = 13

Solution steps

x^{2} + y^{2} + 6 x - 4 y = 0

Rewrite

x^{2} + y^{2} + 6 x - 4 y = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 2)^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 2), r = 13

f (x) = x^{2} + 2 x + 1

y^{2} = 28 x

3 x^{2} - 3 y = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 1

f (x) = x^{2} - 4 x - 5

What is x^2+y^2+6x-4y=0 ?
The solution to x^2+y^2+6x-4y=0 is Circle with (a,b)=(-3,2),r=sqrt(13)