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Popular >

foci y^2=28x

Solution

foci

y^{2} = 28 x

Solution

(7, 0)

Solution steps

Rewrite

y^{2} = 28 x

in the standard form:

4 \cdot 7 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 7

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + 7, 0)

Refine

(7, 0)

Popular Examples

3 x^{2} - 3 y = 0

foci (x^2)/(25)-(y^2)/(16)=1 foci

\frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 1

vertices f(x)=x^2-4x-5 vertices

f (x) = x^{2} - 4 x - 5

(y^2}{16}-\frac{x^2)/4 =1

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

x^{2} - 2 x + 8 y + 9 = 0

Frequently Asked Questions (FAQ)

What is the foci y^2=28x ?
The foci y^2=28x is (7,0)