What is 2y-x^2+24-2x=0 ?

The solution to 2y-x^2+24-2x=0 is Parabola with (h,k)=(-1,-25/2),p= 1/2

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2y-x^2+24-2x=0

2 y - x^{2} + 24 - 2 x = 0

(h, k) = (- 1, - \frac{25}{2}), p = \frac{1}{2}

Solution steps

2 y - x^{2} + 24 - 2 x = 0

Rewrite

2 y - x^{2} + 24 - 2 x = 0

in the standard form

4 \cdot \frac{1}{2} (y - (- \frac{25}{2})) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - \frac{25}{2}), p = \frac{1}{2}

\frac{( x - ( - 2.93 ) ^{2} )}{4.49} + \frac{y ^{2}}{1.34} = 2

(q) = 2 q^{2} - 40 p + 600

\frac{( y - 5 ) ^{2}}{4} = \frac{40 ( x + 0 )}{4}

x^{2} - x - k (x) = 0

10 x^{2} - 256 = 300 f (x) in d

What is 2y-x^2+24-2x=0 ?
The solution to 2y-x^2+24-2x=0 is Parabola with (h,k)=(-1,-25/2),p= 1/2