What is ((x+5)^2)/(25)-((y+1^2))/(36)=1 ?

The solution to ((x+5)^2)/(25)-((y+1^2))/(36)=1 is Parabola with (h,k)=(-5,-37),p= 25/144

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((x+5)^2)/(25)-((y+1^2))/(36)=1

\frac{( x + 5 ) ^{2}}{25} - \frac{( y + 1 ^{2} )}{36} = 1

(h, k) = (- 5, - 37), p = \frac{25}{144}

Solution steps

\frac{( x + 5 ) ^{2}}{25} - \frac{y + 1 ^{2}}{36} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{25} - \frac{y + 1 ^{2}}{36} = 1

in the standard form:

4 \cdot \frac{25}{144} (y - (- 37)) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - 37), p = \frac{25}{144}

(y - 3)^{2} - x = 16

(1 - x)^{2} = x^{2} + y^{2}

4 x^{2} - 3 y - 8 x + 6 y + 1 = 0

x^{2} + 10000 s + 500000 = 0

(x + 7)^{2} = (y + 2)

What is ((x+5)^2)/(25)-((y+1^2))/(36)=1 ?
The solution to ((x+5)^2)/(25)-((y+1^2))/(36)=1 is Parabola with (h,k)=(-5,-37),p= 25/144