What is (y^2)/(64)-(x^2)/(36)=1 ?

The solution to (y^2)/(64)-(x^2)/(36)=1 is Hyperbola with (h,k)=(0,0),a=8,b=6

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(y^2)/(64)-(x^2)/(36)=1

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

(h, k) = (0, 0), a = 8, b = 6

Solution steps

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

Rewrite

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{8 ^{2}} - \frac{( x - 0 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 8, b = 6

x^{2} + y^{2} + 6 x - 2 y - 15 = 0

\frac{y ^{2}}{4} - \frac{x ^{2}}{5} = 1

\frac{x ^{2}}{49} + \frac{y ^{2}}{25} = 1

y^{2} = x + 4

\frac{x ^{2}}{81} - \frac{y ^{2}}{9} = 1

What is (y^2)/(64)-(x^2)/(36)=1 ?
The solution to (y^2)/(64)-(x^2)/(36)=1 is Hyperbola with (h,k)=(0,0),a=8,b=6