What is f(x)(a+2)=3x^2+2 ?

The solution to f(x)(a+2)=3x^2+2 is Parabola with (h,k)=(0, 2/(a+2)),p=(a+2)/(12)

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f(x)(a+2)=3x^2+2

f (x) (a + 2) = 3 x^{2} + 2

(h, k) = (0, \frac{2}{a + 2}), p = \frac{a + 2}{12}

Solution steps

y (a + 2) = 3 x^{2} + 2

Rewrite

y (a + 2) = 3 x^{2} + 2

in the standard form:

4 \cdot \frac{a + 2}{12} (y - \frac{2}{a + 2}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{2}{a + 2}), p = \frac{a + 2}{12}

3 y = 4 x^{2}

y = - \frac{1}{500} (x - 100)^{2} + 20

3 x^{2} + 11 s + 10 = 0

17 x^{2} + 25 y = 425

x - 5 x + y^{2} + 7 x - 9 = 0

What is f(x)(a+2)=3x^2+2 ?
The solution to f(x)(a+2)=3x^2+2 is Parabola with (h,k)=(0, 2/(a+2)),p=(a+2)/(12)