What is (g(x)4)=4x^2-8x+1 ?

The solution to (g(x)4)=4x^2-8x+1 is Parabola with (h,k)=(1,-3/4),p= 1/4

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(g(x)4)=4x^2-8x+1

(g (x) 4) = 4 x^{2} - 8 x + 1

(h, k) = (1, - \frac{3}{4}), p = \frac{1}{4}

Solution steps

y \cdot 4 = 4 x^{2} - 8 x + 1

Rewrite

y \cdot 4 = 4 x^{2} - 8 x + 1

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{3}{4})) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - \frac{3}{4}), p = \frac{1}{4}

0 = 2 x^{2} - y - 12 x + 11

y + 1 = x^{2}

4 u^{2} + 20 v = 0

y \leq - x^{2}

5 x^{2} + 25 x + 10 y = 15

What is (g(x)4)=4x^2-8x+1 ?
The solution to (g(x)4)=4x^2-8x+1 is Parabola with (h,k)=(1,-3/4),p= 1/4