What is e^{ln(y)}=e^{2*ln(x)} ?

The solution to e^{ln(y)}=e^{2*ln(x)} is Parabola with (h,k)=(0,0),p= 1/4

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e^{ln(y)}=e^{2*ln(x)}

e^{l n (y)} = e^{2 \cdot l n (x)}

(h, k) = (0, 0), p = \frac{1}{4}

Solution steps

e^{l n (y)} = e^{2 l n (x)}

Rewrite

e^{l n (y)} - e^{2 l n (x)} = 0

in the standard form

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

x = 1 - (y + 2)^{2}

\frac{s ^{2} - 2 p + 6 p}{( s + 2 )} = 1

f, f (x)^{- 1} (x) = \frac{0.75}{10 - x}

T (n) = T (n - 1) + n^{2}

2 y = - 4 \cdot (x + 2)^{2} + m + 5

What is e^{ln(y)}=e^{2*ln(x)} ?
The solution to e^{ln(y)}=e^{2*ln(x)} is Parabola with (h,k)=(0,0),p= 1/4