What is the vertices X^2 ?

The vertices X^2 is Minimum (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices X^2

vertices

X^{2}

Minimum (0, 0)

Solution steps

y = X^{2}

The parabola parameters are:

a = 1, b = 0, c = 0

x_{v} = - \frac{b}{2 a}

X_{v} = - \frac{0}{2 \cdot 1}

Simplify

X_{v} = 0

Plug in

X_{v} = 0

to find the

y_{v}

value

y_{v} = 0

Therefore the parabola vertex is

(0, 0)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (0, 0)

3 - x^{2}

y = x^{2} - 5 x + 6

y = x^{2} - 4 x + 5

f (x) = 3 x^{2}

y = 4 x^{2} - 8 x + 7