What is the vertices 18x-9x^2-9 ?

The vertices 18x-9x^2-9 is Maximum (1,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices 18x-9x^2-9

vertices

18 x - 9 x^{2} - 9

Maximum (1, 0)

Solution steps

y = 18 x - 9 x^{2} - 9

Rewrite

y = 18 x - 9 x^{2} - 9

in the form

y = a x^{2} + b x + c

y = - 9 x^{2} + 18 x - 9

The parabola parameters are:

a = - 9, b = 18, c = - 9

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{18}{2 ( - 9 )}

Simplify

- \frac{18}{2 ( - 9 )} : 1

x_{v} = 1

Plug in

x_{v} = 1

to find the

y_{v}

value

y_{v} = 0

Therefore the parabola vertex is

(1, 0)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 9

Maximum (1, 0)

+ s^{2} + 2 s + 2

f (x) = x^{2} + 7 x + 12

f (x) = x^{2} + 7 x + 10

y = 2 x^{2} - 3 x + 1

y^{2} - 2 y - 12 x + 25 = 0