What is the foci (x+5)^2=-20(y-2) ?

The foci (x+5)^2=-20(y-2) is (-5,-3)

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foci (x+5)^2=-20(y-2)

foci

(x + 5)^{2} = - 20 (y - 2)

(- 5, - 3)

Solution steps

Rewrite

(x + 5)^{2} = - 20 (y - 2)

in the standard form:

4 (- 5) (y - 2) = (x - (- 5))^{2}

(h, k) = (- 5, 2), p = - 5

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 5, 2)

along the y-axis

(- 5, 2 + p)

= (- 5, 2 + (- 5))

Refine

(- 5, - 3)

x^{2} + 6 x - 8 y + 1 = 0

y = x^{2} + 1

290 (8 x + 0.5 x^{2} - 1.4)

y = - 3 x^{2} - 12 x - 9

2 - 3 x^{2}