What is the foci y=(9x-2)x3 ?

The foci y=(9x-2)x3 is (1/9 ,-35/108)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y=(9x-2)x3

foci

y = (9 x - 2) x 3

(\frac{1}{9}, - \frac{35}{108})

Solution steps

Rewrite

y = (9 x - 2) x \cdot 3

in the standard form

4 \cdot \frac{1}{108} (y - (- \frac{1}{3})) = (x - \frac{1}{9})^{2}

(h, k) = (\frac{1}{9}, - \frac{1}{3}), p = \frac{1}{108}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{1}{9}, - \frac{1}{3})

along the y-axis

(\frac{1}{9}, - \frac{1}{3} + p)

= (\frac{1}{9}, - \frac{1}{3} + \frac{1}{108})

Refine

(\frac{1}{9}, - \frac{35}{108})

x^{2} = - 24 y

y = 12 x^{2}

(x + 3)^{2} - 2

5 x + 3 y^{2} = 0

y = 2 x^{2} - 3 x 8