What is the foci y=2x^2-3x8 ?

The foci y=2x^2-3x8 is (6,-575/8)

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foci y=2x^2-3x8

foci

y = 2 x^{2} - 3 x 8

(6, - \frac{575}{8})

Solution steps

Rewrite

y = 2 x^{2} - 3 x \cdot 8

in the standard form

4 \cdot \frac{1}{8} (y - (- 72)) = (x - 6)^{2}

(h, k) = (6, - 72), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(6, - 72)

along the y-axis

(6, - 72 + p)

= (6, - 72 + \frac{1}{8})

Refine

(6, - \frac{575}{8})

12 + 4 x - x^{2}

y = 2 x^{2} - 5 x + 5

5 x^{2} + 30 x + 24 y = 51

x^{2} + 8 y = 0

y^{2} + 6 y + 2 x + 1 = 0