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Popular >

foci y=2x^2-5x+5

Solution

foci

y = 2 x^{2} - 5 x + 5

Solution

(\frac{5}{4}, 2)

Solution steps

Rewrite

y = 2 x^{2} - 5 x + 5

in the standard form

4 \cdot \frac{1}{8} (y - \frac{15}{8}) = (x - \frac{5}{4})^{2}

(h, k) = (\frac{5}{4}, \frac{15}{8}), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{5}{4}, \frac{15}{8})

along the y-axis

(\frac{5}{4}, \frac{15}{8} + p)

= (\frac{5}{4}, \frac{15}{8} + \frac{1}{8})

Refine

(\frac{5}{4}, 2)

Popular Examples

foci 5x^2+30x+24y=51 foci

5 x^{2} + 30 x + 24 y = 51

foci x^2+8y=0 foci

x^{2} + 8 y = 0

foci y^2+6y+2x+1=0 foci

y^{2} + 6 y + 2 x + 1 = 0

foci (y+5)^2=-16(x-3)foci

(y + 5)^{2} = - 16 (x - 3)

foci (x+3)^2=-12(y+4)foci

(x + 3)^{2} = - 12 (y + 4)

Frequently Asked Questions (FAQ)

What is the foci y=2x^2-5x+5 ?
The foci y=2x^2-5x+5 is (5/4 ,2)