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Popular >

foci x^2+x-1

Solution

foci

x^{2} + x - 1

Solution

(- \frac{1}{2}, - 1)

Solution steps

Rewrite

y = x^{2} + x - 1

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{5}{4})) = (x - (- \frac{1}{2}))^{2}

(h, k) = (- \frac{1}{2}, - \frac{5}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{1}{2}, - \frac{5}{4})

along the y-axis

(- \frac{1}{2}, - \frac{5}{4} + p)

= (- \frac{1}{2}, - \frac{5}{4} + \frac{1}{4})

Refine

(- \frac{1}{2}, - 1)

Popular Examples

foci y=-x^2+2 foci

y = - x^{2} + 2

foci (y-5)^2=12(x+3)foci

(y - 5)^{2} = 12 (x + 3)

foci y=2x^2+16x+29 foci

y = 2 x^{2} + 16 x + 29

foci y=(x+5)^2 foci

y = (x + 5)^{2}

foci x^2+2x+6 foci

x^{2} + 2 x + 6

Frequently Asked Questions (FAQ)

What is the foci x^2+x-1 ?
The foci x^2+x-1 is (-1/2 ,-1)