What is the foci x^2-4x-8y-12=0 ?

The foci x^2-4x-8y-12=0 is (2,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci x^2-4x-8y-12=0

foci

x^{2} - 4 x - 8 y - 12 = 0

(2, 0)

Solution steps

Rewrite

x^{2} - 4 x - 8 y - 12 = 0

in the standard form

4 \cdot 2 (y - (- 2)) = (x - 2)^{2}

(h, k) = (2, - 2), p = 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(2, - 2)

along the y-axis

(2, - 2 + p)

= (2, - 2 + 2)

Refine

(2, 0)

(x - 6)^{2} = - 4 y

4 t^{2} + 1

t^{2} + 2 t - 48

x = - \frac{1}{2} (y - 4)^{2} + \frac{1}{2}

x^{2} + 8 x - 4 y - 36 = 0