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Popular >

foci t^2+2t-48

Solution

foci

t^{2} + 2 t - 48

Solution

(- 1, - \frac{195}{4})

Solution steps

Rewrite

y = t^{2} + 2 t - 48

in the standard form

4 \cdot \frac{1}{4} (y - (- 49)) = (t - (- 1))^{2}

(h, k) = (- 1, - 49), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 1, - 49)

along the y-axis

(- 1, - 49 + p)

= (- 1, - 49 + \frac{1}{4})

Refine

(- 1, - \frac{195}{4})

Popular Examples

foci x=-1/2 (y-4)^2+1/2 foci

x = - \frac{1}{2} (y - 4)^{2} + \frac{1}{2}

foci x^2+8x-4y-36=0 foci

x^{2} + 8 x - 4 y - 36 = 0

foci 4x^2+8x+6 foci

4 x^{2} + 8 x + 6

foci y=(2x-1)(5x-6)foci

y = (2 x - 1) (5 x - 6)

foci y=x^2-5x+6 foci

y = x^{2} - 5 x + 6

Frequently Asked Questions (FAQ)

What is the foci t^2+2t-48 ?
The foci t^2+2t-48 is (-1,-195/4)