What is the foci+(x+2)^2-4 ?

The foci+(x+2)^2-4 is (-2,-15/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci+(x+2)^2-4

foci

+ (x + 2)^{2} - 4

(- 2, - \frac{15}{4})

Solution steps

Rewrite

y = (x + 2)^{2} - 4

in the standard form:

4 \cdot \frac{1}{4} (y - (- 4)) = (x - (- 2))^{2}

(h, k) = (- 2, - 4), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 2, - 4)

along the y-axis

(- 2, - 4 + p)

= (- 2, - 4 + \frac{1}{4})

Refine

(- 2, - \frac{15}{4})

(x - 4)^{2} = - 8 (y + 2)

- 3 x^{2} - x + 4

y = \frac{( - 6 ( r + 4 r ^{2} ) + 9 r ^{2} + 6 r ) ^{2}}{9 r ^{2}}

y^{2} + 2 y - 4 x + 9 = 0

(x - 5) (x + 2)