What is the foci (y-8)^2=16(x-4) ?

The foci (y-8)^2=16(x-4) is (8,8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (y-8)^2=16(x-4)

foci

(y - 8)^{2} = 16 (x - 4)

(8, 8)

Solution steps

Rewrite

(y - 8)^{2} = 16 (x - 4)

in the standard form:

4 \cdot 4 (x - 4) = (y - 8)^{2}

(h, k) = (4, 8), p = 4

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(4, 8)

along the x-axis

(4 + p, 8)

= (4 + 4, 8)

Refine

(8, 8)

y = \frac{x ^{3} - 3 x ^{2} - 4 x}{x - 4}

y = s^{2}

3 x^{2} - 31 x + 56 - (x - 8)

y^{2} = - 25 x

(x + 2)^{2} = 20 (y - 5)