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Popular >

foci y=+x^2-x

Solution

foci

y = + x^{2} - x

Solution

(\frac{1}{2}, 0)

Solution steps

Rewrite

y = x^{2} - x

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{1}{4})) = (x - \frac{1}{2})^{2}

(h, k) = (\frac{1}{2}, - \frac{1}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{1}{2}, - \frac{1}{4})

along the y-axis

(\frac{1}{2}, - \frac{1}{4} + p)

= (\frac{1}{2}, - \frac{1}{4} + \frac{1}{4})

Refine

(\frac{1}{2}, 0)

Popular Examples

foci x^2+8x-16 foci

x^{2} + 8 x - 16

foci y=+3x^2+24x-51 foci

y = + 3 x^{2} + 24 x - 51

foci x=(2y-1)^2 foci

x = (2 y - 1)^{2}

foci y=x^2-10x-24 foci

y = x^{2} - 10 x - 24

foci y=92x^2 foci

y = 92 x^{2}

Frequently Asked Questions (FAQ)

What is the foci y=+x^2-x ?
The foci y=+x^2-x is (1/2 ,0)