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Popular >

foci y=16-x^2

Solution

foci

y = 16 - x^{2}

Solution

(0, \frac{63}{4})

Solution steps

Rewrite

y = 16 - x^{2}

in the standard form:

4 (- \frac{1}{4}) (y - 16) = (x - 0)^{2}

(h, k) = (0, 16), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 16)

along the y-axis

(0, 16 + p)

= (0, 16 + (- \frac{1}{4}))

Refine

(0, \frac{63}{4})

Popular Examples

foci y=196x^2-112x-240 foci

y = 196 x^{2} - 112 x - 240

foci y=+x^2-2x-3 foci

y = + x^{2} - 2 x - 3

foci y=x^2-5x3 foci

y = x^{2} - 5 x 3

foci x^2-3x+4 foci

x^{2} - 3 x + 4

foci x=((y-3)^2)/8+5 foci

x = \frac{( y - 3 ) ^{2}}{8} + 5

Frequently Asked Questions (FAQ)

What is the foci y=16-x^2 ?
The foci y=16-x^2 is (0, 63/4)