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Popular >

foci x^2=8(y-2)

Solution

foci

x^{2} = 8 (y - 2)

Solution

(0, 4)

Solution steps

Rewrite

x^{2} = 8 (y - 2)

in the standard form:

4 \cdot 2 (y - 2) = (x - 0)^{2}

(h, k) = (0, 2), p = 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 2)

along the y-axis

(0, 2 + p)

= (0, 2 + 2)

Refine

(0, 4)

Popular Examples

foci x^2-2x+5 foci

x^{2} - 2 x + 5

foci (y-2)^2=8(x-5)foci

(y - 2)^{2} = 8 (x - 5)

foci (x+1)^2=(y+4)foci

(x + 1)^{2} = (y + 4)

foci y=-x^2+4x+3 foci

y = - x^{2} + 4 x + 3

foci x^2-4x-5y+7=0 foci

x^{2} - 4 x - 5 y + 7 = 0

Frequently Asked Questions (FAQ)

What is the foci x^2=8(y-2) ?
The foci x^2=8(y-2) is (0,4)