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Popular >

foci x^2=8(y+4)

Solution

foci

x^{2} = 8 (y + 4)

Solution

(0, - 2)

Solution steps

Rewrite

x^{2} = 8 (y + 4)

in the standard form:

4 \cdot 2 (y - (- 4)) = (x - 0)^{2}

(h, k) = (0, - 4), p = 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, - 4)

along the y-axis

(0, - 4 + p)

= (0, - 4 + 2)

Refine

(0, - 2)

Popular Examples

foci y^2+4x=0 foci

y^{2} + 4 x = 0

foci y=-3(x+1)^2-1 foci

y = - 3 (x + 1)^{2} - 1

foci y=x(x-4)foci

y = x (x - 4)

foci x+y^2=0 foci

x + y^{2} = 0

foci 2x^2+9x-56 foci

2 x^{2} + 9 x - 56

Frequently Asked Questions (FAQ)

What is the foci x^2=8(y+4) ?
The foci x^2=8(y+4) is (0,-2)