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Popular >

foci x^2+14x+48

Solution

foci

x^{2} + 14 x + 48

Solution

(- 7, - \frac{3}{4})

Solution steps

Rewrite

y = x^{2} + 14 x + 48

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - (- 7))^{2}

(h, k) = (- 7, - 1), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 7, - 1)

along the y-axis

(- 7, - 1 + p)

= (- 7, - 1 + \frac{1}{4})

Refine

(- 7, - \frac{3}{4})

Popular Examples

foci 2x^2+7x-4 foci

2 x^{2} + 7 x - 4

foci x^2+14x+26 foci

x^{2} + 14 x + 26

foci 5x^2-11x-12 foci

5 x^{2} - 11 x - 12

foci-(x-3)^2-4 foci

- (x - 3)^{2} - 4

foci y=+(x-7)^2+8 foci

y = + (x - 7)^{2} + 8

Frequently Asked Questions (FAQ)

What is the foci x^2+14x+48 ?
The foci x^2+14x+48 is (-7,-3/4)