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Popular >

foci x^2+x-4

Solution

foci

x^{2} + x - 4

Solution

(- \frac{1}{2}, - 4)

Solution steps

Rewrite

y = x^{2} + x - 4

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{17}{4})) = (x - (- \frac{1}{2}))^{2}

(h, k) = (- \frac{1}{2}, - \frac{17}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{1}{2}, - \frac{17}{4})

along the y-axis

(- \frac{1}{2}, - \frac{17}{4} + p)

= (- \frac{1}{2}, - \frac{17}{4} + \frac{1}{4})

Refine

(- \frac{1}{2}, - 4)

Popular Examples

foci (x+6)^2=9(y-1)foci

(x + 6)^{2} = 9 (y - 1)

foci x^2-2x-6y-5=0 foci

x^{2} - 2 x - 6 y - 5 = 0

foci 81y^2 foci

81 y^{2}

foci-x^2+10x-5 foci

- x^{2} + 10 x - 5

foci 16t^2+48t+4 foci

16 t^{2} + 48 t + 4

Frequently Asked Questions (FAQ)

What is the foci x^2+x-4 ?
The foci x^2+x-4 is (-1/2 ,-4)