What is the foci (x-1)^2=4(y-2) ?

The foci (x-1)^2=4(y-2) is (1,3)

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foci (x-1)^2=4(y-2)

foci

(x - 1)^{2} = 4 (y - 2)

(1, 3)

Solution steps

Rewrite

(x - 1)^{2} = 4 (y - 2)

in the standard form:

4 \cdot 1 \cdot (y - 2) = (x - 1)^{2}

(h, k) = (1, 2), p = 1

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(1, 2)

along the y-axis

(1, 2 + p)

= (1, 2 + 1)

Refine

(1, 3)

y = + 5 - x^{2}

y = (0.5 - x)^{2}

25 x^{2} - 4

2 x^{2} - 8 y = 6 x^{2} + 20 y

y = 3 x^{2} - 35 x