What is the foci 2x^2-8y=6x^2+20y ?

The foci 2x^2-8y=6x^2+20y is (0,-7/4)

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foci 2x^2-8y=6x^2+20y

foci

2 x^{2} - 8 y = 6 x^{2} + 20 y

(0, - \frac{7}{4})

Solution steps

Rewrite

2 x^{2} - 8 y = 6 x^{2} + 20 y

in the standard form:

4 (- \frac{7}{4}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{7}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + (- \frac{7}{4}))

Refine

(0, - \frac{7}{4})

y = 3 x^{2} - 35 x

y^{2} - 6 y - 2 x + 7 = 0

y = - 0.0000848 x^{2} - 0.006005 x + 1.004

y^{2} - \frac{3}{4} x = 0

40 x - 5 x^{2}