What is the foci y^2-3/4 x=0 ?

The foci y^2-3/4 x=0 is (3/16 ,0)

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foci y^2-3/4 x=0

foci

y^{2} - \frac{3}{4} x = 0

(\frac{3}{16}, 0)

Solution steps

Rewrite

y^{2} - \frac{3}{4} x = 0

in the standard form:

4 \cdot \frac{3}{16} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{3}{16}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + \frac{3}{16}, 0)

Refine

(\frac{3}{16}, 0)

40 x - 5 x^{2}

x = - \frac{3}{8} (y - 2)^{2} - 1

y = 3 x^{2} - 7

y = p (x - h)^{2} + k

(x - 3)^{2} = - 12 y