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Popular >

foci y=2x^2-x

Solution

foci

y = 2 x^{2} - x

Solution

(\frac{1}{4}, 0)

Solution steps

Rewrite

y = 2 x^{2} - x

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{1}{8})) = (x - \frac{1}{4})^{2}

(h, k) = (\frac{1}{4}, - \frac{1}{8}), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{1}{4}, - \frac{1}{8})

along the y-axis

(\frac{1}{4}, - \frac{1}{8} + p)

= (\frac{1}{4}, - \frac{1}{8} + \frac{1}{8})

Refine

(\frac{1}{4}, 0)

Popular Examples

foci x=-1/12 (y+10)^2-6 foci

x = - \frac{1}{12} (y + 10)^{2} - 6

foci y=2x^2-9 foci

y = 2 x^{2} - 9

foci y=2x^2-3 foci

y = 2 x^{2} - 3

foci y=x^2+8x+18 foci

y = x^{2} + 8 x + 18

foci 5x^2+6x-4 foci

5 x^{2} + 6 x - 4

Frequently Asked Questions (FAQ)

What is the foci y=2x^2-x ?
The foci y=2x^2-x is (1/4 ,0)