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Popular >

foci x^2-12x+35

Solution

foci

x^{2} - 12 x + 35

Solution

(6, - \frac{3}{4})

Solution steps

Rewrite

y = x^{2} - 12 x + 35

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 6)^{2}

(h, k) = (6, - 1), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(6, - 1)

along the y-axis

(6, - 1 + p)

= (6, - 1 + \frac{1}{4})

Refine

(6, - \frac{3}{4})

Popular Examples

foci 4.905x^2+8x-30 foci

4.905 x^{2} + 8 x - 30

foci x=-1/2 (y-2)^2+5 foci

x = - \frac{1}{2} (y - 2)^{2} + 5

foci (x+6)^2=-8(y+9)foci

(x + 6)^{2} = - 8 (y + 9)

foci (2+x)^2 foci

(2 + x)^{2}

foci (40x^3)/(3x)foci

\frac{40 x ^{3}}{3 x}

Frequently Asked Questions (FAQ)

What is the foci x^2-12x+35 ?
The foci x^2-12x+35 is (6,-3/4)